The amplitude of the electric field of a plane electromagnetic wave in air is `6.0xx10^(-4) V m^(-1)`. The amplitude of the imagnetic field will be

Options

A. `1.8xx10^(5)T`1
B. `5.0xx10^(3)T`
C. `2.0xx10^(-4)T`
D. `2.0xx10^(-12)T`

Explanation

To find the amplitude of the magnetic field (B₀) of a plane electromagnetic wave given the amplitude of the electric field (E₀), we can use the relationship between the electric field, magnetic field, and the speed of light (c). The relationship is given by:

\[ E_0 = B_0 \cdot c \]

Where:
- \( E_0 \) is the amplitude of the electric field,
- \( B_0 \) is the amplitude of the magnetic field,
- \( c \) is the speed of light in a vacuum (approximately \( 3 \times 10^8 \, \text{m/s} \)).

### Step-by-Step Solution:

1. **Identify the given values**:
- Amplitude of the electric field, \( E_0 = 6.0 \times 10^{-4} \, \text{V/m} \)
- Speed of light, \( c = 3.0 \times 10^8 \, \text{m/s} \)

2. **Rearrange the equation to solve for \( B_0 \)**:
\[ B_0 = \frac{E_0}{c} \]

3. **Substitute the known values into the equation**:
\[ B_0 = \frac{6.0 \times 10^{-4} \, \text{V/m}}{3.0 \times 10^8 \, \text{m/s}} \]

4. **Perform the calculation**:
- First, calculate the division:
\[ B_0 = 6.0 \times 10^{-4} \div 3.0 \times 10^8 = 2.0 \times 10^{-12} \, \text{T} \]

5. **Result**:
- The amplitude of the magnetic field \( B_0 \) is \( 2.0 \times 10^{-12} \, \text{T} \).

### Final Answer:
The amplitude of the magnetic field is \( 2.0 \times 10^{-12} \, \text{T} \).

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