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Statement-1: H(2)O(2) liberates O(2) whe...

Statement-1: `H_(2)O_(2)` liberates `O_(2)` when it reacts with acidified `KMnO_(4)` solution
Statement-2: `KMnO_(4)` oxidised `H_(2)O_(2)` to `O_(2)`.

A

Statement-1 is true, statement-2 is true, statement-2 is a correct explanation for statement-1

B

Statement-1 is true, statement-2 is true, statement-2 is not correct explanation for statement-1

C

Statement-1 is true, statement-2 is false

D

Statement-1 is false, statement-2 is true

Text Solution

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A
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Assertion. H_(2)O_(2) liberates O_(2) when it reacts with acidified KMnO_(4) solution. Reason. KMnO_(4) oxidises H_(2)O_(2) to O_(2)

KMnO_(4)+H_(2)O_(2) rarr Mn^(2+)-O_(2)

Knowledge Check

  • A : H_2O liberate O_2 an reaction with KMnO_4 in acidic medium. R : KMnO_4 oxidises H_2O_2" to " O_2 .

    A
    If both Assertion & Reason are true and the reason is the correct explanation of the assertion, then mark (1)
    B
    If both Assertion & Reason are true but the reason is not the correct explanantion of the assertion, then mark (2)
    C
    If assertion is true statements but Reason is false, then mark (3)
    D
    If both Assertion and Reason are false statements, then mark (4)
  • Alkaline KMnO_(4) and acidified K_(2)Cr_(2)O_(7) are :

    A
    Catalysts
    B
    Reducing agents
    C
    Oxidising agents
    D
    None of these
  • 20ml of H_(2)O_(2) is reacted completely with acidified K_(2)Cr_(2)O_(7) solution. 40mL of K_(2)Cr_(2)O_(7) was required to oxidise the H_(2)O_(2) solution to reach equivalent point. Which of the following statements is/are correct?

    A
    The `H_(2)O_(2)` solution is 5M
    B
    The volume strength of `H_(2)O_(2)` is 56V
    C
    The volume strength of `H_(2)O_(2)` is 112V
    D
    If 40 mL of `5//8H_(2)O_(2)` is further added to the 10mL of above `H_(2)O_(2)` solution the volume strength of the resulting solution is changed to 16.8V
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    What is the weight in gram of available O_(2) per litre from a solution of H_(2)O_(2) , 10 mL of which when titrated with N//20 KMnO_(4) solution required 25 mL for the reaction ? 2KMnO_(4)+5H_(2)O_(2)+4H_(2)SO_(4)to 5O_(2)+8H_(2)O+2KHSO_(4)+2MnSO_(4)

    In a reaction excess of H_(2)O_(2) is added to 0.1 mole of acidified KMnO_(4) solution. Then the S.T.P volume of O_(2) liberated is

    H_(2)O_(2) is an unstable liquid . On standing or on heating it decomposes to H_(2)O and O_(2) . H_(2)O_(2) can acts as oxidising agent and reducing agent . The concentration of H_(2)O_(2) is expressed differently with volume strength and the concentration of H_(2)O_(2) at a particular time is measured by titrating it with acidified KMnO_(4) or by titrating liberated I_(2) from acidified KI and H_(2)O_(2) with hypo solution . A sample of H_(2)O_(2) has 3.4 g of H_(2)O_(2) in 100 mL solution . The bottle containing this sample was kept at 25^(0)C for 15 days then 20mL of this sample is treated with excess KI and the liberated iodine requires 50 mL , 0.2 M Na_(2)S_(2)O_(3) solution . Assume the volume of solution remains unchanged . The volume of H_(2)O_(2) sample (after 15 days ) that is required to reduce 40 mL of 0.2 M acidified KMnO_(4) solution is :

    For completely reacting with 400 mL of 1 N acidified KMnO_(4) solution, what volume of a 10 volume sample of H_(2)O_(2) is needed?

    Assertion If 10 mL of a H_(2)O_(2) solution required 8.00 mL of 0.02 M acidified KMnO_(4) solution for complete oxidation, 12.50 mL of same H_(2)O_(2) will oxidise completely to 5.00 mL of 0.10 M Na_(2)C_(2)O_(4) solution. Reason H_(2)O_(2) act as both oxidising as well as reducing agent.