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Statement-1: K(2)CO(3) cannot be prepare...

Statement-1: `K_(2)CO_(3)` cannot be prepared by Le-blanc method.
Statement-2: Sodium nitrate when heated gives `NO_(2)` gas.
Statement-3: `NaO_(2)` is paramagnetic while `Na_(2)O_(2)` is diamagnetic.

A

FFT

B

FTT

C

TFT

D

TTF

Text Solution

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A
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Knowledge Check

  • Na_(2)S_(2)O_(3) is prepared by :

    A
    reaching `H_(2)S_(2)O_(3)` with `NaOH`.
    B
    reacting `Na_(2)SO_(4)` with S is alkaline medium.
    C
    heating `NaOH` and S
    D
    reducing `Na_(2)SO_(4)` with S in acidic medium.

  • Give reason for the statement [Ni(CN)_(4)]^(2-) is diamagnetic while [NiCl_(4)]^(2-) is paramagnetic in nature .

    A
    In `[NiCl_(4)]^(2-)` no unpaired electrons are present while in `[Ni(CN)_(4)]^(2-)` two unpaired electrons are present
    B
    In `[Ni(CN)_(4)]^(2-)` , no unpaired electrons are present while in `[NiCl_(4)]^(2-)` two unpaired electrons are present .
    C
    `[NiCl_(4)]^(2-)` shows `dsp^(2)` hybridisation hence it is paramagnetic .
    D
    `[Ni(CN)_(4)]^(2-)` shows `sp^(3)` hybridisation hence it is diamagnetic .

  • AgCl when heated with Na_(2)CO_(3) gives

    A
    `Ag_(2)O`
    B
    `Ag`
    C
    `Ag_(2)CO_(3)`
    D
    `NaAgCO_(3)`

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    Statement-1: Al forms H_(2) when reacts with NaOH. Statement-2: Al_(2)O_(3) is amphoteric by nature. Statement-3: Al_(2)O_(3) is a neutral oxide.

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