`BF_(3)+Hfto`

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`H^(+)[BF_(4)]^(-)`
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Write balanced equations for: BF_(3)+LiHto

BF_(3) is.

NH_(3)and BF_(3) from adduct readily because they from

PH_(3) and BF_(3) form an adduct readily because they form

Which is/are true in case of BF_(3) ?

(a) Explain why BF_(3) exists whereas BH_(3) does not. (b) Compare the B-F bond length in BF_(3) and BF_(4)^(-)

In the reaction underset(" (Adduct)")(NH_(3)+BF_(3)rarrNH_(3)*BF_(3)) Choose the correct statement.

Knowledge Check

  • NH_(3)and BF_(3) from adduct readily because they from

    A
    Ionic bond
    B
    Covalent bond
    C
    Co-ordinate bond
    D
    Hydrogen bond

  • Which is/are true in case of BF_(3) ?

    A
    It is volatile liquid even at room temperature
    B
    It is Lewis acid
    C
    It has planer geometry
    D
    It forms adduct with `NH_(3)`

  • In the reaction underset(" (Adduct)")(NH_(3)+BF_(3)rarrNH_(3)*BF_(3)) Choose the correct statement.

    A
    Hybridisaton of 'N' in `NH_(3)` changes in adduct
    B
    Hybridisation of 'N' in adduct is `sp^(3)`
    C
    Here, `NH_(3)` is acting as a Lewis base while `BF_(3)` as a Lewis acid
    D
    Hybridisation of 'B' in `BF_(3)` changes in adduct