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Assertion: Boron always froms covalent b...

Assertion: Boron always froms covalent bond.
Reason: The small size of `B^(3+)` favours formation of covalent bond.

A

Statement-1 is true, statement-2 is true, statement-2 is a correct explanation for statement-1

B

Statement-1 is true, statement-2 is true, statement-2 is not correct explanation for statement-1

C

Statement-1 is true, statement-2 is false

D

Statement-1 is false, statement-2 is true

Text Solution

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The correct Answer is:
A
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Boron always forms covalent compound. The small size of B^(3+) favours formation of covalent compound.

Knowledge Check

  • Assertion. Boron always forms covalent compounds. Reason. The small size of B^(3+) favours formation of covalent bonds.

    A
    If both assertion and reason are true, and reason is the true explanation of the assertion.
    B
    If both assertion and reason are true, but reason not is the true explanation of the assertion.
    C
    If assertion is true, but reason is false.
    D
    If both assertion and reason are false.

  • Assertion (A) : Boron always forms covalent bond. Reason (R) : The small size of B^(3+) favours formation of covalent bond.

    A
    Both A and R are true and R is the correct explanation of A
    B
    Both A and R are true but R is not a correct explanation of A
    C
    A is true but R is false
    D
    A is false but R is true

  • Boron always forms covalent compound. The small size of B^(3+) favours formation of covalent compound.

    A
    If both `(A)` are correct and `( R)` is the correct explanation of `(A)`.
    B
    If both `(A)` and `( R)` are correct but `( R)` is not the correct explanation of `(A)`.
    C
    If `(A)` is correct, but `( R)` is incorrect.
    D
    If `(A)` is incorrect, but `( R)` is correct.
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