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Explain by giving equation for the react...

Explain by giving equation for the reaction :
(i) `Mn^(3+)` disproportionates to `Mn^(2+)` and `MnO_(2)` in acidic medium.
(ii) `KMnO_(4)` heated with KOH

Text Solution

Verified by Experts

(i) `2Mn^(+3) +2H_(2)O to Mn^(+2) +MnO_(2) +4H^(+)`
(ii) ` 4KMnO_(4)+4KOH to 4K_(2)MnO_(4)+2H_(2)O+2H_(2)O+O_(2)`
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MnO_4^- and _______are formed by the disproportionation of MnO_4^(2-) in acidic medium.

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Knowledge Check

  • MnO_4^-2 undergoes disproportionation reaction in acidic medium but MnO_4^- does not because

    A
    In `MnO_4^-2`,Mn is in intermediate oxidation state
    B
    In `MnO_4^-2`,Mn is in lowest oxidation state
    C
    In `MnO_4^-2` ,Mn is in intermediate oxidation state
    D
    none of the above

  • In acid solution, the reaction MnO_(4)^(-) rarr Mn^(2+) involves

    A
    Oxidation by 3 electrons
    B
    Reduction by 3 electrons
    C
    Oxidation by 5 electrons
    D
    Reduction by 5 electrons

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