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Ag^(+) + NH3 hArr [Ag(NH3)]^(+) , K1=3....

`Ag^(+) + NH_3 hArr [Ag(NH_3)]^(+) , K_1=3.5xx10^(-3)`
, `[Ag(NH_3)]^(+) + NH_3 hArr [Ag(NH_3)_2]^(+) , K_2=1.7xx10^(-3)` . Calculate the formation constant of `[Ag(NH_3)_2]^+`. What is the instability constant ?

Text Solution

Verified by Experts

Overall formation constant is the product of successive formation constants, `K_c=K_1xxK_2`.
Formation constant of `[Ag(NH_3)_2]^(+) =3.5xx10^(-3)xx1.7xx10^(-3)=5.95xx10^(-6)`
Instability constant is the inverse of the stability constant, `1/K_c=1/(5.95xx10^(-6))=1.7xx10^7`.
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Knowledge Check

  • Ag^(+)+NH_3 hArr Ag(NH_3)^(+),K_1=3.5xx10^(-3) Ag(NH_3)^(+)+NH_3 hArr [Ag(NH_3)_2^(+),K_2=1.7xx10^(-3) Then, the formation constant of [Ag(NH_3)_2] from Ag^(+) and NH_3 is

    A
    `1.7xx10^(-3)`
    B
    `5.92 xx 10^(-6)`
    C
    `1.8 xx 10^(3)`
    D
    `1.7 xx 10^7`

  • Observe the following equations NH_(3) + Ag^(+) hArr (Ag (NH_(3)) ]^(+) , " " K_(1) = 1.6 xx 10^(3) [ Ag(NH_(3) ]^(+) + NH_(3) hArr [ Ag (NH_(3))_(2) ]^(+), K_(2) = 6.8 xx 10^(3) the equilibrium constant for the following reaction, Ag^(+) + 2NH_(3) hArr [ Ag (NH_(3))_(2) ]^(+) is

    A
    `6.008 xx 10^(3)`
    B
    `1.088 xx 10^(7)`
    C
    `1.088 xx 10^(8)`
    D
    `1.028 xx 10^(3)`

  • The hybridisation of Ag in the complex [Ag(NH_3)_2]^(+) is

    A
    `sp`
    B
    `sp^2`
    C
    `sp^3`
    D
    `dsp^2`

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