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0.12g of organic compound containing sul...

0.12g of organic compound containing sulphur on treatment with Conc. `HNO_(3)` in a carius tube and then with excess of `BaCl_(2)` produced 0.233g of `BaSO_(4)`. % of 'S' in compound ...........

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The correct Answer is:
1
`%S=(32 xx "weight of" BaSO_(4) xx 100)/(233 xx "weight of organic compound")10%, 1 xx 10 =1`
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0.4037 g of an organic substance containing sulphur was heated with conc. nitric acid in a carius tube. On precipitation with BaCl_(2) , 0.1963 g of BaSO_(4) was produced. Determine the percentage of sulphur in the compound.

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Knowledge Check

  • 0.32g of an organic compound containing sulphur produces 0.233g of BaSO_(4) . Percentage of sulphur in the compound is

    A
    20
    B
    50
    C
    10
    D
    80

  • 0.16 g of an organie compound containing sulphur produces 0.233 g of BaSO_(4) Percentage of sulphur in the compound is

    A
    0.2
    B
    0.8
    C
    0.5
    D
    0.1

  • 0.5 gm of an organic substance containing phosphorous was heated with conc. HNO_(3) in the Carius tube. The phosphoric acid thus formed was precipitated with magnesia mixture ( MgNH_(4)PO_(4) ) which on ignition gave a residue of 1.0 gm of magnesium pyrophosphate ( Mg_(2)P_(2)O_(7) ). The percentage of phosphorous in the organic compound is :

    A
    0.5585
    B
    0.2972
    C
    0.1918
    D
    0.205

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    1 g of an organic compoud on treatment with fuming nitric acid and BaCl_(2) solution gave 0.29125 g of BaSO_(4) calculate the percentage of sulphur in the compound.

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