Home
Class 12
CHEMISTRY
The difference between number of alpha a...

The difference between number of `alpha` and `beta` particles emitted during the conversion of `U_(92)^(238) to Pb_(82)^(206)` is

Text Solution

Verified by Experts

The correct Answer is:
2

`""_(92) U^(238) to ""_(82) Pb^(206) + a(""_(2) He^(4)) + b (""_(-1) beta^(0)) , 238 = 206 + 4a + 0`
`a = ((238 - 206)/(4)) = (32)/(4) = 8 alpha , 92= 82 + ( 8 xx 2) - b , b = 16 + 82 - 92 = 16 - 10 = 6 beta , (a - b) = 8 - 6 = 2 `
Promotional Banner

Topper's Solved these Questions

  • NUCLEAR CHEMISTRY

    AAKASH SERIES|Exercise PRACTICE SHEET - 2 (Match the following questions)|2 Videos
  • NOBLE GASES

    AAKASH SERIES|Exercise PRACTICE SHEET - 2 (Single more than one option questions)|5 Videos
  • PERIODIC TABLE

    AAKASH SERIES|Exercise QUESTIONS FOR DESCRIPTIVE ANSWERS|37 Videos

Similar Questions

Explore conceptually related problems

Number of beta particles emitted during the decay of ""_(92)^(235) U to ""_(82)^(207)Pb

The number of alpha- and beta - particles emitted during the transformation of ""_(90)^(232) Th to ""_(82)^(208) Pb is respectively

The number of beta - particle emitted during the change ""_(a) X^(c) to ""_(a) Y^(b) is :

The number of alpha and beta particles, respectiyely, emitted in the radioactive decay ""_(90)X^(200) to _(80)Y^(168) are,

How many alpha and beta - particles are emitted when uranium nucleus (""_(92)^(238)U) decay to ""_(82)^(214)Pb ?

What is the difference between alpha - particle and helium atom ?

Number of alpha - particles produced during the decay process of U - 235 to Pb - 207

The number of alpha particle in the nuclear reaction ""_(90)^(238) Th to ""_(81)^(212) Bi are : ____

The number of electrons in ""_(92)U^(238) is