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The difference between number of alpha a...

The difference between number of `alpha` and `beta` particles emitted during the conversion of `U_(92)^(238) to Pb_(82)^(206)` is

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The correct Answer is:
2
`""_(92) U^(238) to ""_(82) Pb^(206) + a(""_(2) He^(4)) + b (""_(-1) beta^(0)) , 238 = 206 + 4a + 0`
`a = ((238 - 206)/(4)) = (32)/(4) = 8 alpha , 92= 82 + ( 8 xx 2) - b , b = 16 + 82 - 92 = 16 - 10 = 6 beta , (a - b) = 8 - 6 = 2 `
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Knowledge Check

  • The number of alpha- and beta - particles emitted during the transformation of ""_(90)^(232) Th to ""_(82)^(208) Pb is respectively

    A
    2,2
    B
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  • The number of beta - particle emitted during the change ""_(a) X^(c) to ""_(a) Y^(b) is :

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    C
    `d- a + [(c- d)/(2)]`
    D
    `d + [ (a- b)/(2)] - c`

  • The number of alpha and beta particles, respectiyely, emitted in the radioactive decay ""_(90)X^(200) to _(80)Y^(168) are,

    A
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    C
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