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The concentration of potassium ions insi...

The concentration of potassium ions inside a biological cell is at least twenty times higher than the outside. The resulting potential difference across the cell is important in several processes such as transmission of nerve impulses and maintaining the ion balance. A simple model for such concentration cell involving a metal M is : `M_((s)) |M_((aq , 0.05 (" molar"))^(+) ||M_((aq, 1 " molar"))^(+) | M_(s)`
For the above electrolytic cell the magnitude of the cell potential `|E_("cell")|=70mV`.
If the 0.05 molar solution of `M^(+)` is replaced by a 0.0025 molar `M^(+)` solution, then the magnitude the cell potential would be

A

`35mV `

B

`70 mV `

C

`140 mV `

D

`700 mV `

Text Solution

Verified by Experts

The correct Answer is:
C

`E_1 = E_0^(0) - (2.303RT)/(nF) log(0.05), 70 =0 -(2.303RT)/(nF) log 0.05`
`((2.303RT)/(nF)) = ((70)/(1.301)), " But " E_2 = E^0 - ((2.303 RT)/(nF)) xx log(2.5 xx 10^(-4))`
`E_2 = 0 - ((70)/(1.303)) xx (-2.602) , E_2 = 140 mV `
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Knowledge Check

  • The concentration of potassium ions inside a biological cell is at least twenty times higher than the outside. The resulting potential difference across the cell is important in several processes such as transmission of nerve impulses and maintaining the ion balance. A simple model for such concentration cell involving a metal M is : M_((s)) |M_((aq , 0.05 (" molar"))^(+) ||M_((aq, 1 " molar"))^(+) | M_(s) For the above electrolytic cell the magnitude of the cell potential |E_("cell")|=70mV . For the above cell

    A
    `E_("cell") lt 0 , DeltaG gt 0`
    B
    `E_("cell") gt 0 , DeltaG lt 0`
    C
    `E_("cell") lt 0 , DeltaG^(0) gt 0`
    D
    `E_("cell") gt 0 , DeltaG^(@) lt 0`
  • Which ions are responsible for the electrical potential across the cells membrane ?

    A
    `Na^(+) & Zn^(2+)`
    B
    `K^(+)& Ba^(2+)`
    C
    `Na^(+)& K^(+)`
    D
    `Na^(+)& Ca^(2+)`
  • The H ion concentration of a solution is 4.75xx10^(-5) M. Then the OH ion concentration of the same solution is

    A
    `4xx10^(-5)` M
    B
    `2.5 xx10^(9)` M
    C
    `1.0xx10^(7)` M
    D
    `2.5xx10^(-10)` M
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