Conductors allow the passage of electric...

Conductors allow the passage of electric current through them. Metallic and electrolytic are the two types of conductors. Current carriers in metallic and electrolytic conductors are free electrons and free ions respectively. Specific conductance or conductivity of the electrolyte solution is given by the following relation: `K= cx (l)/(A)`
where, c=1/R is the conductance and 1/A is the cell constant, Molar conductance `(^^_m)` and equivalence conductance `(^^_e)` of an electrolyte solution are calculated using the following similar relations:
`^^_m = K xx (1000)/(M) ^^_(e) = K xx (1000)/(N)` where, M and N are the molarity and normality of the solution respectively. Molar conductance of strong electrolyte depends on concentration : `^^_m = ^^_m^(0) - b sqrt(C)`
`^^_m^(0)` = molar conductance at infinite dilution
C = concentration of the solution b = constant
The degrees of dissociation of weak electrolytes are calculated as`alpha = (^^_m)/(^^_m^(0)) = (^^_e)/(^^_e^(0))`
Which of the following decreases on dilution of electrolytic solution?

Equivalent conductance

Molar conductance

Specific conductance

Conductance

Verified by Experts

The correct Answer is:

specific conductance

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Conductors allow the passage of electric current through them. Metallic and electrolytic are the two types of conductors. Current carriers in metallic and electrolytic conductors are free electrons and free ions respectively. Specific conductance or conductivity of the electrolyte solution is given by the following relation: K= cx (l)/(A) where, c=1/R is the conductance and 1/A is the cell constant, Molar conductance (^^_m) and equivalence conductance (^^_e) of an electrolyte solution are calculated using the following similar relations: ^^_m = K xx (1000)/(M) ^^_(e) = K xx (1000)/(N) where, M and N are the molarity and normality of the solution respectively. Molar conductance of strong electrolyte depends on concentration : ^^_m = ^^_m^(0) - b sqrt(C) ^^_m^(0) = molar conductance at infinite dilution C = concentration of the solution b = constant The degrees of dissociation of weak electrolytes are calculated as alpha = (^^_m)/(^^_m^(0)) = (^^_e)/(^^_e^(0)) For which of the following electrolytic solution ^^_m and ^^_e are equal ?

`BaCl_2`

`KCl`

`Al_2(SO_4)_3`

`CaCl_2`

`Lambda= Lambda^(0) " as " C to 1 `

`Lambda= Lambda^(0) " as " C to 0`

`Lambda= Lambda^(0) " as " C to oo`

`Lambda= Lambda^(0) " as " C to sqrt(b)`

increases with dilution

decreases with dilution

remains unchanged with dilution

depends on mass of electrolyte