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The E^@ at 25^@C for the following reac...

The `E^@` at `25^@C ` for the following reaction is 0.22 V ` H_(2(g)) + 2AgCl_((s)) to 2Ag_((s)) + 2HCl_((aq))` . If the equilibrium constant at ` 25^@ C ` is ` 2.8 xx 10^(x)` , x is

Text Solution

Verified by Experts

The correct Answer is:
7

`E^(@) = (0.059)/(2) log_(10)^(K) implies K = 2.8 xx 10^(7) implies x =7`
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Knowledge Check

  • The reaction , 1//2H_(2(g)) + AgCl_((s)) to H_((aq))^(+) + Cl_((aq))^(-) + Ag_((s)) occurs in the galvanic cell :

    A
    `Ag|AgCl_((s)) | KCl_(("soln")) | AgNO_(3("soln"))|Ag`
    B
    `Pt,H_(2(s)) |HCl_(("soln"))|AgNO_(3("soln")) | Ag `
    C
    `Pt,H_(2(g)) | HCl_(("soln")) | AgCl_((s))|Ag`
    D
    `Pt, H_(2(g)) ||KCl_(("soln"))||AgCl_((s))|Ag `
  • For the reaction Pt// H_2 (1 atm) // H^(+) (aq) // // Cl^(-) (aq) // AgCl // Ag , K_(c) (equilibrium constant ) is represented as

    A
    `K_(c) = ([Cl^(-)][AgCl])/([H^(+)][H_2])`
    B
    `K_c = [H^(+)][Cl^(-)]`
    C
    `K_(c) = ([H^(+)][H_2])/([Cl^(-)][AgCl])`
    D
    `K_(c) = ([H_2])/([Ag])`
  • The standard e.m.f. for the cell reaction, 2Cu^(+)(aq) to Cu(s) + Cu^(2+)(aq) is + 0.36V at 298 K. The equilibrium constant of the reaction is

    A
    `5 xx 10^6`
    B
    `1.4 xx 10^12`
    C
    `7.4 xx 10^12`
    D
    `1.3 xx 10^6`
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