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For helium vander Waals parameter bis 0....

For helium vander Waals parameter bis 0.024 lit/mol. The diameter of helium is nearly 

A

`1.7 A^@`

B

`2.7A^@`

C

`3.7 A^@`

D

`4.0 A^@`

Text Solution

Verified by Experts

The correct Answer is:
B
`b = 4 xx 6 xx 10^(23) xx V_("molecule")`
`0.04 xx 10^(-3) = 4 xx 6 xx 10^(23) xx 4/3 pi (d/2)^2`
`implies d = 2.67 xx 10^(-10) m = 2.67 Å`.
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Knowledge Check

  • 2 moles of gas contained in a four litre flask exerts a pressure of Il atm at 27^@C . If vander Waals parameter bis 0.05 l/mol, the value of 'a' (in atm "lt"^(2) "mol"^(-2) ) is

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