As per second law of thermodynamics a pr...

As per second law of thermodynamics a process taken place spontaneously if and only if the entropy of the universe increases due to the process. Change in entropy is given by
`Delta S = (Q_(rev))/(T)`
What is the change in entropy of the universe due to the following reaction occuring at `27^(@)C` ?
`A + 2B rarr C + 2D, Delta H = +1.8 kJ mol^(-1)`
Molar entropy values of A, B, C and D are 1,2,3 and `4 JK^(-1) mol^(-1)` respectively.

`6JK^(-1) mol^(-1)`

`8JK^(-1) mol^(-1)`

`1.2 JK^(-1) mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:

`Delta S_("universe") = Detla S_("system") + Delta S_("surroundings")`
`= (Sigma S_(P)- Sigma S_(R )) + ((-Delta H_("system"))/(T))`
`= (2(4) + 3-2(2)-1) + ((-1.8 xx 10^(3))/(300))`
`= 6-6 = 0`

Topper's Solved these Questions

CHEMICAL THERMODYNAMICS
AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE-III) (LEVEL - II (ADVANCED) MATRIX MATCHING TYPE QUESTIONS)|2 Videos
CHEMICAL THERMODYNAMICS
AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE-III) (LEVEL - II (ADVANCED) INTEGER TYPE QUESTIONS)|5 Videos
CHEMICAL THERMODYNAMICS
AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE-III) (LEVEL - II (ADVANCED) MORE THAN ONE CORRECT ANSWER TYPE QUESTIONS)|5 Videos
CHEMICAL THERMODYANMICS
AAKASH SERIES|Exercise Questions For Descriptive Answers|28 Videos
ELECTRON MIGRATION EFFECTS
AAKASH SERIES|Exercise QUESTIONS FOR DESCRIPTIVE ANSWERS|10 Videos

As per second law of thermodynamics a process taken place spontaneously if and only if the entropy of the universe increases due to the process. Change in entropy is given by Delta S = (Q_(rev))/(T) A gas C_(V) = (0.2 T) Cal K^(-1) . What is the change in its entropy when one mole of it is heated from 27^(@)C to 127^(@)C at constant volume ?

`20calK^(-1) mol^(-1)`

`15calK^(-1) mol^(-1)`

`35calK^(-1) mol^(-1)`

`25calK^(-1) mol^(-1)`

As per second law of thermodynamics a process taken place spontaneously if and only if the entropy of the universe increases due to the process. Change in entropy is given by Delta S= (Q_("rev"))/(T) A gas C_(V) = (0.2T) "Cal" K^(-1) . What is the change in its entropy when one mole of it is heated from 27^(@)C " to" 127^(@)C at constant volume?

`20 "cal "K^(-1) mol^(-1)`

`15 "cal "K^(-1) mol^(-1)`

`35 "cal "K^(-1) mol^(-1)`

`25 "cal "K^(-1) mol^(-1)`

For change in entropy, units are

mol/lit

`mol. lit^(-1) sec^(-1)`

`J. mol^(-1) K^(-1)`

`s^(-1)`

Text Solution

Topper's Solved these Questions

Similar Questions

Knowledge Check

For change in entropy, units are

Similar Questions

AAKASH SERIES-CHEMICAL THERMODYNAMICS-LECTURE SHEET (EXERCISE-III) (LEVEL - II (ADVANCED) LINKED COMPREHENSION TYPE QUESTIONS)