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The least random state of H(2)O system i...

The least random state of `H_(2)O` system is

A

Ice

B

Liquid water

C

Steam

D

Randominess is same in all

Text Solution

Verified by Experts

The correct Answer is:
A

Entropy of `x lt l lt g`
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H_(2)O_(2) acts both as oxidant and reductant. H_(2)O and O_(2) are products when H_(2)O_(2) acts as oxidant and reductant respectively. The strength of H_(2)O_(2) is expressed in terms of molarity, normality, % strength and volume strength. H_(2)O_(2) decomposes as H_(2)O_(2)rarrH_(2)+1//2O_(2)(g) i.e., one mole O_(2) is released from 2 mole H_(2)O_(2) .x. .volume. strength of H_(2)O_(2) means 1 volume (mL or litre) of H_(2)O_(2) sample released x volume (mL or litre) O_(2) gas at NTP on its decomposition. Hence molarity = x//11.2 moles per litre, i.e., normality of H_(2)O_(2)=x//5.6 Thus volume strength, i.e., x=5.6xx Normality. Weigth of H_(2)O_(2) (in gm) present in 100 mL H_(2)O_(2) solution is called percentage strength of H_(2)O_(2) How much volume of H_(2)O_(2) solution of 22.4 .vol. strength is required to oxidise 6.3 gm oxalic acid

Identify the correct statements from the following . (i) Oxygen shows -2,-1,+1 and +2 oxidation states. (ii) The thermal stability of H_(2)O, H_(2)Se and H_(2)S follows the order H_(2)O ltH_(2)S lt H_(2)Se. (iii) The reducing nature of H_(2)Se,H_(2)S and H_(2) Te follows the order H_(2)S ltH_(2)Se ltH_(2)Te

Knowledge Check

  • The structure of H_(2)O_(2) is

    A
    Planar
    B
    Non-Polar
    C
    Spherical
    D
    Linear
  • The approximate mass of H_(2)O_(2) present in 200mL of 100 volume H_(2)O_(2) solution is

    A
    33 grams
    B
    30 grams
    C
    60 grams
    D
    66 grams
  • The least soluble hydroxide in H_(2)O is

    A
    `LiOH`
    B
    `NaOH`
    C
    `RbOH`
    D
    `CsOH`
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    Pure H_(2)O_(2) is not very stable and decomposes in the presence of light or on standing or heating overset((-1))(H_(2)O_(2l))+overset((2-)) (H_(2)O_((l)))+overset((0))(O_(2(g))) The oxidation state of oxygen in H_(2)O_(2) is 1 it is oxidistion state of zero in O_(2) and is reduced to an oxidation state of -2 in H_(2)O . Thus, this decomposition is an example of auto oxidation reduction reaction or disproportionation reaction. Pure H_(2)O is

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