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A flask of 1L having NH(3)(g) at 2.0atm ...

A flask of 1L having `NH_(3)(g)` at 2.0atm and 200K is connected with another flask of vol 800ml having HCl(g) at 8atm & 200K through tube of negligible volume. The two gases reacts to form `NH_(4)Cl(s)` with evolution of 43 KJ/mol heat. If heat capacity of at constant volume is 20J/K/mol and neglecting heat capacity of flask and solid, volume of solid formed and its pressure (R = 0.08).
The final pressure in the flask is

A

5.375KJ

B

4.375KJ

C

6.8KJ

D

6.375J

Text Solution

Verified by Experts

The correct Answer is:
A
`NH_(3(g)) + HCl_((g)) rarr NH_(4)Cl_((s)), Delta H = - 43.0KJ`
`{:("Initial mole", (1 xx 2)/(0.08 xx 200), (8 xx 0.8)/(0.08 xx 200)0,0),(,= 0.125,=0.4,),("Final moles",0,0.275,0.125):}`
`:.` heat product = `0.125 xx 43 = 5.375 KJ`
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Knowledge Check

  • A flask of 1L having NH_(3) (g) at 2.0 atm and 200K is connected with another flask of vol 800ml having HCl(g) at 8 atm & 200K through a narrow tube of negligible volume. The two gases reacts to form NH_(4)Cl(s) with evolution of 43 KJ/mol heat. If heat capacity of at constant volume is 20J/K/mol and neglecting heat capacity of flask, solid, volume of solid formed and its pressure (R = 0.08) The final pressure in the flask is

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    14.39 atm
    B
    1.49 atm
    C
    16.39 atm
    D
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  • The molar specific heat of a gas at constant volume is 20 Joule/gm mol/K. The value of gamma for it will be

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    `11//10`
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  • The specific heat of Argon at constant volume is 0.3122kJ/kg K. Find the specific heat of Argon at constant pressure if R = 8.314 kJ/k mole K. (Molecular weight of argon = 39.95)

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