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The velocity of a gas molecule present i...

The velocity of a gas molecule present in a cubic vessel in a particular direction is 100 cm/sec. The side of that cubic vessel is 10 cm. The time taken for one collision in a given particular direction on one face is 

A

0.2 sec

B

5 sec

C

0.5 sec

D

50 sec

Text Solution

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The correct Answer is:
A
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A square loop of side 12 cm with its sides parallel to X and velocity of 8 cm s in the positive x-direction in an environment containing a magnetic field in the positive z-direction. The field is neither uniform in space nor constant in time. It has a gradient of 10 T cm along the negative x-direction (that is it increases by 103 T cm- as one moves in the negative x-direction), and it is decreasing in time at the rate of 103 Ts. Determine the direction and magnitude of the induced current in axes is moved with a the loop if its resistance is 4.50 m2. Sol. Given, side of loop a = 12 cm . Area of loop (A) = a = (12) = 144 cm = 144 x 10 m? (. Area of square = (side))

Knowledge Check

  • The velocity of a gas molecule present in a cubic vessel in X-direction is 1000 cm / sec. The side of that cubic vessel is 10 cm. The number of bombardments made by the molecule on one face in X-direction in one second is

    A
    200
    B
    400
    C
    25
    D
    50

  • The rms velocity of nitrogen molecule in a cylinder containing nitrogen gas at 17°C is 5 xx 10^(12) m/s. If the diameter of the nitrogen molecule is roughly 2.0A^(@) then the time taken for the collision between two nitrogen molecules

    A
    `2 xx 10^(-13) S`
    B
    `4 xx 10^(-20) S`
    C
    `3 xx 10^(-13) S`
    D
    `1 xx 10^(-13) S`

  • The rms velocity of nitrogen molecule in a cylinder containing nitrogen gas at 17^(@)C is 5xx10^(12) m/s. If the diameter of the nitrogen molecule roughly 2.0 A^(@) then the time taken for the collision between two nitrogen molecules

    A
    `2xx10^(-13)S`
    B
    `4.4xx10^(-20)S`
    C
    `3xx10^(-13)S`
    D
    `1xx10^(-13)S`

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