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Work function of sodium and copper is 2....

Work function of sodium and copper is 2.3 eV and 4.5 eV respectively.Ratio of their threshold wavelength will be…..

A

`1:2`

B

`2:1`

C

`4:1`

D

`1:4`

Text Solution

Verified by Experts

The correct Answer is:
B
In `phi=hf_(0)=(h_(c))/(lambda_(0)),lambda_(c)`=constant
`therefore phi prop (1)/(lambda_(0))`
`(phi_(Na))/(phi_(cu))=(lambda_(0)(cu))/(lambda_(0)(Na))`
`(2.3)/(4.5)=(lambda_(0)(cu))/(lambda_(0)(Na))`
`(1)/(2)~~(lambda_(0)(cu))/(lambda_(0)(Na)) therefore (lambda_(0)(cu))/(lambda_(0)(Na))=(2)/(1)`
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Knowledge Check

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