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If the solubility product of MOH is 1xx1...

If the solubility product of MOH is `1xx10^(-10) mol^(2).dm^(-2)` . Then the `p^(H)` of the its aqueous solution will be

A

12

B

9

C

6

D

3

Text Solution

Verified by Experts

The correct Answer is:
B
` K_(sp) = 1 xx 10 ^(_10 ) M, [OH] = 10 ^(-5) M, pOH = 5`
` therefore pH = 9`
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