PCl(5) in solid state exists as PCl(4)^(...

`PCl_(5)` in solid state exists as `PCl_(4)^(+) and PCl_(6)^(-)` and also in some solvents it undergoes dissociation as `2PCl_(5) hArr PCl_(4)^(+) +PCl_(6)^(-)`
Which statement is wrong ?

Solution assumes colour of Hin when `p ^(K_(In) )+ 1`

Solution assumes colour of `In^(-) ` When pH =` p ^(K_(In) )-1`

Solution assumes colour Hin when pH =` p ^(K_(In)) +1`

Solution assumes colour of `In^(-) ` when pH =` p ^(K_(In)) -1`

Verified by Experts

The correct Answer is:

C, D

When `pH gt PK_(In) +1, " colour " ` of ` In^(-) `
When `pH lt PK_(In) - 1 , ` Colour of Hin

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PCl_(5) in solid state exists as PCl_(4)^(+) and PCl_(6)^(-) and also in some solvents it undergoes dissociation as 2PCl_(5) hArr PCl_(4)^(+) +PCl_(6)^(-) The geometry and hybridisation of PCl_(6)^(-) is

Octahedral , `sp^3`

Octahedral , `sp^3d^2`

Trigonal bipyramid `sp^3d`

See - saw , `sp^3 d `

Tetrahderal , `sp^3`

Octahedral , `sp^(3) d^(2)`

Linear , sp

Angular , `sp^2`

`90^(@)`

`120^(@)`

`180^(@)`

`109^(@).28.`