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The de-Broglie equation treats an electr...

The de-Broglie equation treats an electron to be

A

a particle

B

a wave

C

ray

D

both (1) and (2)

Text Solution

Verified by Experts

The correct Answer is:
D
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Knowledge Check

  • The de-Broglie.s equation treats an electron to be

    A
    a particle
    B
    a wave
    C
    ray
    D
    both (1) and (2)

  • An electron of charge e and mass m moving with an initial velocity v_(0)hat(i) is subjected to all electric field E_(0)hat(j) . The de-Broglie wavelength of the electron at a time t is (Initial de-Broglie wavelength of the electron = lambda_(0) )

    A
    `lambda_(0)`
    B
    `lambda_(0) sqrt(1 + (e^(2) E_(0)^(2)t^(2))/(m^(2) v_(0)^(2)))`
    C
    `(lambda_(0))/(sqrt(1 + (e^(2) E_(0)^(2)t^(2))/(m^(2) v_(0)^(2))))`
    D
    `(lambda_(0))/(sqrt(1 + (e^(2) E_(0)^(2)t^(2))/(mv_(0)^(2))))`

  • False statement about the de-Broglie.s wavelength of an electron in the Bohr.s orbit is

    A
    equal to the circumference of the first orbit
    B
    equal to twice the circumference of the first orbit
    C
    equal to half the circumference of the first orbit
    D
    equal to one fourth of the circumference of the first orbit

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    The De-Broglie wavelength of an electron moving with a velocity of 1.5xx10^8ms//s is equal to that of a photon The ratio of kinetic energy of the electron to that of the photon (c=3xx10^8m//s )

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