According to Bohr model of atom...

According to Bohr model of atom

The radius of `n^(th)` orbit a `n^(2)`

The total energy of electron in `n^(th)` orbit `alpha(1)/(n)`

The angular momentum electron is integral multiples of `h//2pi`

The magnitude of potential energy of an electron is an orbit greater than kinetic energy

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The correct Answer is:

A, C, D

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According to Bohr's model of an atom, the electrons revolve round the nucleus in

orbits

sub-orbits

orbitals

electron cloud

the radius of nth orbit is proportional to `n^(2)`

the total energy of the electron in the `n^(th)` orbit is inversely proportional to n

the angular momentum of the electron in an orbit is an integral multiple of `(h)/(2pi)`

the magnitude of the potential energy of the electron in an orbit is greater than its kinetic energy

independent of which orbit it is in

zero

positive

increases with the quantum number n