Home
Class 11
CHEMISTRY
A certain transition in H-spectrum from...

A certain transition in H-spectrum from an axcited state to ground state in one (or) more steps gives rise to total 10 lines. How many of these belongs to UV-spectrum.

Text Solution

Verified by Experts

The correct Answer is:
4(UV-region i.e., `5 rarr 1, 4 rarr 1, 3 rarr 1, 2 rarr 1`)
Promotional Banner

Topper's Solved these Questions

  • ATOMIC STRUCTURE

    AAKASH SERIES|Exercise Level-II (Type - II) (Lecture sheet-2 (subjective/Analytical type Questions))|8 Videos

  • ATOMIC STRUCTURE

    AAKASH SERIES|Exercise Level-II (Type - II) (Practice sheet-2 (subjective/Analytical type Questions))|8 Videos

  • ATOMIC STRUCTURE

    AAKASH SERIES|Exercise Level-II (Type - II) (Lecture sheet - 1 (subjective/Analytical type Questions))|8 Videos

  • AROMATIC HYDROCARBONS

    AAKASH SERIES|Exercise OBJECTIVE EXERCIES - 3 (RECENT AIPMT/NEET QUESTIONS)|10 Videos

  • CHEMICAL BONDING

    AAKASH SERIES|Exercise OBJECTIVE EXERCISE -3 (RECENT AIPMT/NEET QUESTIONS )|39 Videos

Similar Questions

Explore conceptually related problems

A certain transition in H spectrum from an excited state to ground state in one or more steps gives rise to total 10 lines. How many of these belong to uv spectrum?

In a certain electronic transition from the quantum level, 'n' to the ground state in atomic hydrogen in one or more steps, no line belonging to the Bracket series is observed. What wave number may be observed in the Balmer series ? (R = Rydberg Constant)

In a certain electronic transition from the quantum level, 'n' to the ground state in atomic hydrogen in one or more steps, no line belonging to the Brackett series is observed. What wave numbers may be observed in the Balmer series? (R=Rydberg Constant)

Atomic hydrogen is excited from the grounds state to the n^(th) state. The number of lines in the emission spectrum will be:

The electrons in the ground state for a single H-atom absorbs a photon of wavelength 97.28 nm and it reaches to maximum level .n. then when it returns from this level to ground state. Maximum numbers of lines can be obtained in its spectrum ?

A gaseous mixture contains hydrogen atoms in the 4^(th) excited state, He^(+) ions in 3^(rd) excited state and Li^(2+) in 2^(nd) excited state. The number of spectral lines obtained in the emission spectrum of this sample when all these atoms/ions return to the ground state is

When electron jumps from higher orbit to lower orbit, then energy is radiated in the form of electro magnetic radiation and these radiations are used to record the emission spectrum Energy of electron may be calculated as E= (2pi^2 m_e Z^2 e^4)/(n^2 h^2) where m_e = rest mass of electron DeltaE = (E_(n_2)- E_(n_1)) = 13.6xxZ^2 xx [1/(n_1^2) - 1/(n_2^2)] eV per atom This equation was also used by Rydberg to calculate the wave number of a particular line in the spectrum. bar(upsilon) = 1/(lambda) = R_H Z^2 [1/(n_1^2) -1/n_2^2] m^(-1) Where , R_H = 1.1 xx 10^7 m^(-1) (Rydberg constant) For Lyman, Balmer, Paschen, Brackett and Pfund series the value of n_1 = 1,2,3,4,5 respectively and n_2 = oo for series limit, If an electron jumps from higher orbit n to ground state than number of spectral line will be ""^nC_2 . Ritz modified the Rydberg equation by replacing the rest mass of electron with reduced mass (mu) . 1/(mu) = 1/(m_N) + 1/(m_e) , Here m_N mass of nucleus , m_e = mass of electron. The emission spectrum of He^+ involves transition of electron from n_1 to n_2 such that n_2 + n_1 = 8 and n_2 - n_1 = 4 . What will be the total number of lines in the spectrum ?

The only electron in the hydrogen atom resides under ordinary conditions on the first orbit. When energy is supplied, the electron moves to higher energy orbit depending on the amount of energy absorbed. When this electron returns to any of the lower orbits, it emits energy. Lyman series is formed when the electron returns to the lowest orbit while Balmer series is formed when the electron returns to second orbit. Similarly, Paschen, Brackett and Pfund series are formed when electron returns to the third, fourth orbits from higher energy orbits respectively (as shown in figure) Maximum number of lines produced when an electron jumps from nth level to ground level is equal to (n(n-1))/(2) . For example, in the case of n = 4, number of lines produced is 6. (4 rarr 3, 4 rarr 2, 4 rarr 1, 3 rarr 2, 3 rarr 1, 2 rarr 1) . When an electron returns from n_(2) to n_(1) state, the number of lines in the spectrum will be equal to ((n_(2) - n_(1))(n_(2)-n_(1) +1))/(2) If the electron comes back from energy level having energy E_(2) to energy level having energy E_(2) then the difference may be expressed in terms of energy of photon as E_(2) - E_(1) = Delta E, lambda = (h c)/(Delta E) . Since h and c are constant, Delta E corresponds to definite energy, thus each transition from one energy level to another will prouce a higher of definite wavelength. THis is actually observed as a line in the spectrum of hydrogen atom. Wave number of the line is given by the formula bar(v) = RZ^(2)((1)/(n_(1)^(2)) - (1)/(n_(2)^(2))) Where R is a Rydberg constant (R = 1.1 xx 10^(7)) (i) First line of a series : it is called .line of logest wavelength. or .line of shortest energy.. (ii) Series limit of last of a series : It is the line of shortest wavelength or line of highest energy. In a single isolated atom in electron makes transition from 5^(th) excited state to 2^(nd) state the maximum number of different types of photons observed as