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(A) Reduction of a metal oxide is easier...

(A) Reduction of a metal oxide is easier if the metal formed is in liquid state at the temperature of reduction .
(R) `Delta G^(@)` for the net reaction, reduction of metal oxide with the reductant, is more-ve when the metal formed is in molten state

A

Both (A) and (R) are true and (R) is the correct explanation of (A)

B

Both (A) and (R) are true and (R) is not the correct explanation of (A)

C

(A) is true but (R) is false

D

Both (A) and (R) are false

Text Solution

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The correct Answer is:
A
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Why is the reduction of a metal oxide if the metal formed is in liquid state at the temperature of reduction?

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Knowledge Check

  • (A) The reduction of metal oxide is easier if the metal is in liquid state at temp of reduction (R) Delta S is -ve and Delta G is + ve

    A
    Both (A) and (R) are true and (R) is the correct explanation of (A)
    B
    Both (A) and (R) are true and (R) is not the correct explanation of (A)
    C
    (A) is true but (R) is false
    D
    Both (A) and (R) are false
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