What is the total number of orbitals present in the shell with the principal quantum number, n = 3

Explanation

For the shell with n=3, the possible values of l are 0,1 and 2 and
Thus there is one 3s orbital (l = 0) and m=0)
There are three 3p orbitals `(l=1, and m=-1,0,+1)` and five 3d orbitals `( = 2 and m = -2, -1,0 +1, +2)`
Therefore the total number of orbitals `= 1 + 3 + 5 = 9`