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The minimum energy required for the phot...

The minimum energy required for the photo emission of electrons from the surface of a metal is `4.95xx10^(-19)J`. Calculate the critical frequency and the corresponding wave length of the photon required to eject the electron.

Text Solution

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`v=7.5xx10^(14)Hz, lambda=400nm`
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The kinetic energy of an electron is 4.55xx10^(-28) kJ . Calculate the de Broglie's wavelength.

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Knowledge Check

  • The energy required to emit an electron from the surface of a metal is called

    A
    Activation energy
    B
    Threshold energy
    C
    Critical energy
    D
    Kinetic energy

  • The energy required to emit an electron from the surface of a metal is called

    A
    Activation energy
    B
    Threshold energy
    C
    Critical energy
    D
    Kinetic energy

  • Electrons with a kinetic energy of 6.023 xx 10^(4) J//mol are evolved from the surface of a metal, when it is exposed to radiation of wavelength of 600 nmn. The minimum amount of energy required to remove an electron from the metal atom is

    A
    `2.3125 xx 10^(-19) J`
    B
    `3 xx10^(-19) J`
    C
    `6.02 xx10^(-19) J`
    D
    `6.62 xx 10^(-32)J`

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