How many moles of `KMnO_(4)` are required to oxidise one mole of ferrous oxalate in acidic medium ?

Explanation

Ferrous oxalate is a dual reducing agent. In acidic medium `MnO_(4)^(-)` oxidises ferrous ion to ferric ion and oxalate ion to `CO_(2)`.
Thus balanced equation for the reaction between the permanganate ion and ferrous oxalate is `3MnO_(4)^(-)+5FeC_(2)O_(4)+24H^(+)rarr 3Mn^(2+)+5Fe^(3+)+10CO_(2)+12H_(2)O`
Thus one mole of `KMnO_(3)` can oxidise 1.67 moles of ferrous oxalate.