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How many moles of KMnO(4) are required t...

How many moles of `KMnO_(4)` are required to oxidise one mole of ferrous oxalate in acidic medium ?

Text Solution

Verified by Experts

Ferrous oxalate is a dual reducing agent. In acidic medium `MnO_(4)^(-)` oxidises ferrous ion to ferric ion and oxalate ion to `CO_(2)`.
Thus balanced equation for the reaction between the permanganate ion and ferrous oxalate is `3MnO_(4)^(-)+5FeC_(2)O_(4)+24H^(+)rarr 3Mn^(2+)+5Fe^(3+)+10CO_(2)+12H_(2)O`
Thus one mole of `KMnO_(3)` can oxidise 1.67 moles of ferrous oxalate.
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Knowledge Check

  • Number of moles of MnO_(4)^(-) required to oxidize one mole of ferrous oxalate completely in acid medium will be:

    A
    7.5 moles
    B
    0.2 moles
    C
    0.6 moles
    D
    0.4 moles

  • Number of moles of KMnO_(4) required to oxidize one mole of Fe(C_(2)O_(4)) in acidic medium is

    A
    0.6
    B
    0.167
    C
    0.2
    D
    0.4

  • Number of moles of KMnO_(4) required to oxidize one mole of Fe(C_(2)O_(4)) in acidic medium is

    A
    0.6
    B
    0.167
    C
    20
    D
    40

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