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Passage-I : When a gas 'A' is passed ...

Passage-I :
When a gas 'A' is passed through dry KOH at low temperature a deep red coloured compound, B and a gas 'C' are obtained. The gas A, on reaction with but -2-ene, followed by treatment with `Zn//H_(2)O` yields acetaldehyde. Identify A, B & C.
What is A

A

`O_(2)`

B

`O_(3)`

C

`SO_(2)`

D

`CO_(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`2KOH+underset((A))underset(uarr)(5O_(3))to underset((B))undersetuarr(2KO_(3))+underset((C ))underset(uarr)(5O_(2))+H_(2)O`
`A=O_(3), B=KO_(3), C=O_(2)`
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Knowledge Check

  • When Cl_(2) gas is passed through hot and conc. Solution of KOH, following compound is formed :

    A
    KCl
    B
    `KClO_(3)`
    C
    `KClO_(2)`
    D
    `KClO_(4)`

  • A bluish green coloured compound 'A' on heating gives two products 'B' and 'C'. A metal 'D' is deposited on passing H_(2) through heated 'B'. The compound 'A' and 'B' are insoluble in water. 'B' is black in colour, dissolves in HCI and on treatment with K_(4)[Fe(CN)_(6)] gives a chocolate brown ppm of compound 'E'. 'C' is colourless, odourless gas and turns lime water milkly. The compounds 'B' and 'C' are respectively

    A
    `CuS, SO_(2)`
    B
    CuO, `CO_(2)`
    C
    FeO, `H_(2)S`
    D
    `Cr_(2)O_(3), CO`

  • A bluish green coloured compound 'A' on heating gives two products 'B' and 'C'. A metal 'D' is deposited on passing H_(2) through heated 'B'. The compound 'A' and 'B' are insoluble in water. 'B' is black in colour, dissolves in HCI and on treatment with K_(4)[Fe(CN)_(6)] gives a chocolate brown ppm of compound 'E'. 'C' is colourless, odourless gas and turns lime water milkly. Compound 'A' is

    A
    `CuSO_(4)`
    B
    `CuCO_(3)`
    C
    `FeSO_(4)`
    D
    `CrCl_(3)`

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