Home
Class 12
CHEMISTRY
A metal ion from the first transition ha...

A metal ion from the first transition has a magnetic moment of 3.87 B.M. How many unpaired electrons are expected to be present in the ion

Text Solution

Verified by Experts

The correct Answer is:
3
`M^(+2) rArr mu = sqrt(n(n+2)) = 3.87 BM rArr n = 3`
Promotional Banner

Topper's Solved these Questions

  • D & F BLOCK ELEMENTS

    AAKASH SERIES|Exercise PRACTICE SHEET-1 (SINGLE OR MORE THAN ONE OPTION QUESTIONS)|16 Videos

  • D & F BLOCK ELEMENTS

    AAKASH SERIES|Exercise PRACTICE SHEET-1 (LINKED COMPREHENSION TYPE QUESTIONS)|6 Videos

  • D & F BLOCK ELEMENTS

    AAKASH SERIES|Exercise LEVEL-II (LECTURE SHEET) (EXERCISE-III)(MATCH OF FOLLOWING QUESTIONS)|9 Videos

  • COMPLEX COMPOUNDS

    AAKASH SERIES|Exercise PRACTICE EXERCISE|45 Videos

  • D - BLOCK ELEMENTS

    AAKASH SERIES|Exercise PRACTICE EXERCISE|50 Videos

Similar Questions

Explore conceptually related problems

How many unpaired electrons are present in divalent manganese ion ?

A substance is found to have a magnetic moment of 3.9 BM. How many unpaired electrons does it contain?

How many unpaired electrons are present in the central metal ion [CoCl_4]^(2-)

Write the configuration of Ni^(2+) . How many unpaired electrons are there in the ion?

Magnetic moment of Mn^(+2) is 5.8 B.M. Hence the number of unpaired electrons presenting the metal ion is

How many 'd' electrons are present in Cr^(2+) ion?

The spin-only magnetic moment of an ion is 3.87 BM. The ion is