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A metal ion from the first transition ha...

A metal ion from the first transition has a magnetic moment of 3.87 B.M. How many unpaired electrons are expected to be present in the ion

Text Solution

Verified by Experts

The correct Answer is:
3
`M^(+2) rArr mu = sqrt(n(n+2)) = 3.87 BM rArr n = 3`
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Knowledge Check

  • Magnetic moment of Mn^(+2) is 5.8 B.M. Hence the number of unpaired electrons presenting the metal ion is

    A
    5
    B
    4
    C
    3
    D
    2

  • The spin-only magnetic moment of an ion is 3.87 BM. The ion is

    A
    `Ti^(2+)`
    B
    `Co^(2+)`
    C
    `Cu^(2+)`
    D
    `Mn^(2+)`

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