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A spring connects two particles of masse...

A spring connects two particles of masses `m_1 and m_2` A horizontal force F acts on `m_1` Ignoring friction, when the elongation of the spring is x then:

A

`a_(2)=(kx)/m_2`

B

`a_(1)=(F-kx)/(m_1)`

C

`F=m_(1)a_(1)+m_(2)a_(2)`

D

`a_(1)=a_(2) =F/(m_(1)+m_(2)` at the time of maximum elongation of the spring .

Text Solution

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The correct Answer is:
A, B, C, D
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Knowledge Check

  • Two masses m_(1) and m_(2) are placed on a smooth horizontal surface and are connected by a string of negligible mass. A horizontal force F is applied on the mass m_(2) as shown in the figure. The tension in the string is

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    D
    `(m_(2)F)/(m_(1))`

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