Home
Class 11
PHYSICS
In the arrangement shown in figur m = mA...

In the arrangement shown in figur m `= m_A m_B = 2mB and m_c = M` . Assume all surfaes to be smooth and pulleys to be light, the acceleration of blcok C is

A

`(3Mg)/(3M+4m)`

B

`(Mg)/(3M+4m)`

C

`(2Mg)/(3M+4m)`

D

`(Mg)/(3m)`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • NEWTONS LAWS OF MOTION

    AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE - VI) (More than one correct answer Type Questions)|2 Videos
  • NEWTONS LAWS OF MOTION

    AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE - VI) (Linked Comprehension Type Questions)|3 Videos
  • NEWTONS LAWS OF MOTION

    AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE - V) (Straight Objective Type Questions)|6 Videos
  • MOTION IN A STRAIGHT LINE

    AAKASH SERIES|Exercise Questions for Descriptive Answers|7 Videos
  • OSCILLATION

    AAKASH SERIES|Exercise QUESTIONS FOR DESCRIPTIVE ANSWERS|12 Videos

Similar Questions

Explore conceptually related problems

Assuming all the surface to be frictionless, acceleration of the block C shown in the figure is :

In the arrangement shown in figure, m_A = 1kg and m_B = 2kg , while all the pulleys and strings are masslesss and frictionless. At t = 0, a force F = 10t starts acting over central pulley in vertically upward direction. If the velocity of A is x xx 10m/s when B loses contact with floor, find x.

All surfaces are smooth. The acceleration of mass m relative to wedge is:

All surfaces are smooth. The acceleration of mass m relative to wedge is

In the arrangement shown in the figure all surfaces are frictionless, the masses of the block are m_1 = 20kg and m_2 = 30kg. The accelerations of masses m_1 and m_2 will be if F = 180N.

In the arrangement shown in the figure if the blocks of masses m and 2m are released from the state of rest tension in the string is ( mu = coefficient of friction string is massless and inextensible pulley is frictionless )