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A block of mass 'm' is placed on wedge o...

A block of mass 'm' is placed on wedge of mass 'M'. If all the surfaces are smooth

Accelaration of wedge 'A' is

A

`(mg sin theta)/(M+ msin ^(2) theta)`

B

`(mgsin theta cos theta)/(M + m sin^(2)theta)`

C

`(mgcos theta)/(M+m sin^(2) thea)`

D

`(mg)/(M+m)`

Text Solution

Verified by Experts

The correct Answer is:
B
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Knowledge Check

  • A block of mass 'M' is placed on the top of a wedge of mass '4M'. All the surfaces are frictionless. The system is released from rest. The distance moved by the wedge at the instant, the block reaches the bottom will be

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    B
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    `g sin theta - a cos theta`
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  • All surfaces are smooth. The acceleration of mass m relative to wedge is:

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    D
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