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A 40kg slab rests on a frictionless floo...

A 40kg slab rests on a frictionless floor. A 10kg block rests on top of the slab. the static coefficient of friction between the block and the slab is 0.60 and The coefficient kinetic friction between the block and the slab is 0.40. A horizontal force of 100N is applied on the 10kg block. Find the resulting acceleration of the slab. `(g=10ms^(-1))`

A

`3ms ^(-2)`

B

`4 ms ^(-2)`

C

`1ms ^(-2)`

D

`2ms ^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • A 2kg block is placed over a 4kg block and both are placed on a smooth horizontal surface. The coefficient of friction between the blocks is 0.20. The acceleration of the two blocks if a horizontal force of 12N is applied to the lower block is

    A
    `2ms^(-2) , 2ms^(-2)`
    B
    `2ms^(-2), 1ms^(-2)`
    C
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    D
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    A
    `2ms^(-2) , 2ms^(-2)`
    B
    `2ms^(-2), 1ms^(-2)`
    C
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    A
    `13/4, 0.6`
    B
    `14/3, 3`
    C
    `13/4, 3`
    D
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