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Half of the chain is lying on a table. T...

Half of the chain is lying on a table. The rest of the chain hangs in equilibrium from both of the ends of the table. Extra length of the hanging chain at one end is 1/8 th of the total length of the chain than that hanging at the other end. The coefficient of friction between table and chain is `25 xx 10^(-4)` the value of x is

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0.5
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Knowledge Check

  • A uniform chain of length L hangs partially from table and held in equilibrium by friction. If greatest length of chain that hangs without slipping is l then the coefficient of friction between chain and table is

    A
    L
    B
    `1/(L+l)`
    C
    `l/(L-l)`
    D
    `l/(L+l)`
  • A homogeneous chain lies in limiting equilibrium on a horizontal table of coefficient of friction 0.5 with part of it hanging over the edge of the table. The fractional length of the chain hanging down the edge of the table is

    A
    `1//2`
    B
    `1//5`
    C
    `1//3`
    D
    `2//3`
  • A homogeneous chain lies in limiting equilibrium on a horizontal table of coefficient of friction 0.5 with part of it hanging over the edge of the table. The fractional length of the chain hanging down the edge of the table is

    A
    `1//2`
    B
    `1//5`
    C
    `1//3`
    D
    `2//3`
  • Similar Questions

    Explore conceptually related problems

    A homogeneous chain lies in limiting equilibrium on a horizontal table of coefficient of friction 0.5 with part of it hanging over the edge of the table. The fractional length of the chain hanging down the edge of the table is

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