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Which of the following options are corre...

Which of the following options are correct for `[Fe(CN)_(6)]^(3-)` complex ?

A

`d^(2)sp^(3)` hybridisation

B

`sp^(3) d^(2)` hybridisation

C

Paramagnetic

D

Diamagnetic

Text Solution

AI Generated Solution

The correct Answer is:
To determine the correct options for the complex \([Fe(CN)_{6}]^{3-}\), we will follow these steps: ### Step 1: Determine the oxidation state of Iron (Fe) The charge of the complex is \(-3\). The cyanide ion (CN) has a charge of \(-1\). Since there are 6 cyanide ions, their total contribution to the charge is \(6 \times -1 = -6\). Let the oxidation state of iron be \(x\). The equation can be set up as follows: \[ x + 6(-1) = -3 \] \[ x - 6 = -3 \] \[ x = +3 \] ### Step 2: Determine the electronic configuration of Iron in this oxidation state Iron has an atomic number of 26, and its electron configuration is: \[ [Ar] 3d^6 4s^2 \] When it loses 3 electrons to form \(Fe^{3+}\), the configuration becomes: \[ [Ar] 3d^5 \] ### Step 3: Analyze the ligand field Cyanide (CN\(^-\)) is a strong field ligand. Strong field ligands cause pairing of electrons in the lower energy d-orbitals (t2g) before occupying the higher energy orbitals (eg). ### Step 4: Fill the d-orbitals For \(Fe^{3+}\) with a \(3d^5\) configuration in the presence of a strong field ligand, the electrons will pair up in the t2g orbitals. The filling will be as follows: - The 5 electrons will occupy the t2g orbitals, resulting in: - t2g: ↑↑↑↑↑ (5 electrons in t2g, no electrons in eg) ### Step 5: Determine the hybridization In an octahedral complex like \([Fe(CN)_{6}]^{3-}\), the hybridization can be determined by the number of orbitals involved in bonding. For this complex: - 2 d-orbitals, 1 s-orbital, and 3 p-orbitals are used for hybridization. Thus, the hybridization is: \[ d^2sp^3 \] ### Step 6: Determine magnetic properties Since there is 1 unpaired electron in the t2g orbitals, the complex is paramagnetic. ### Final Conclusion Based on the analysis: 1. The hybridization is \(d^2sp^3\) - **True** 2. The hybridization is \(sp^3d^2\) - **False** 3. The complex is paramagnetic - **True** 4. The complex is diamagnetic - **False** ### Correct Options The correct options for the complex \([Fe(CN)_{6}]^{3-}\) are: - \(d^2sp^3\) hybridization (True) - Paramagnetic (True)

To determine the correct options for the complex \([Fe(CN)_{6}]^{3-}\), we will follow these steps: ### Step 1: Determine the oxidation state of Iron (Fe) The charge of the complex is \(-3\). The cyanide ion (CN) has a charge of \(-1\). Since there are 6 cyanide ions, their total contribution to the charge is \(6 \times -1 = -6\). Let the oxidation state of iron be \(x\). The equation can be set up as follows: \[ x + 6(-1) = -3 ...
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Same number of unpaired electron is observed in which of the following complexes (a) [MnCl_(6)]^(3-) (b) [Fe(CN)_(6)]^(3-) ( c) [CoF_(6)]^(3-) (d) [Ni(NH_(3))_(6)]^(2+)

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Knowledge Check

  • The hybridization of iron atom in [Fe(CN)_6]^(3-) complex is

    A
    `sp^3`
    B
    `d^2 sp^3`
    C
    `sp^3 d^2`
    D
    `dsp^2`
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