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I. CH(3) - CH(2) - CH(2) - CH(2) - OH ...

I. `CH_(3) - CH_(2) - CH_(2) - CH_(2) - OH`
II. `CH_(3) - CH_(2) - underset(OH)underset(|)(CH) - CH_(3)`
III. `CH_(3) - underset(OH) underset(|)overset(CH_(3))overset(|)(C) - CH_(3)`
IV. `CH_(3) - underset(CH_(3))underset(|)(CH) - CH_(2) - OH`
V. `CH_(3) - CH_(2) - O - CH_(2) - CH_(3)`
VI. `CH_(3) - O - CH_(2) - CH_(2) - CH_(3)`
VII. `CH_(3) - O - underset(CH_(3))underset(|)(CH) - CH_(3)`
Which of the above compounds form pairs of metamers ?

Text Solution

AI Generated Solution

To determine which of the given compounds form pairs of metamers, we first need to understand what metamerism is. Metamerism is a type of isomerism that occurs when two compounds have the same functional group but differ in the arrangement of alkyl groups around that functional group. This is commonly observed in ethers. Let's analyze the provided compounds step by step: ### Step 1: Identify the functional groups We need to look for compounds that have the same functional group. In this case, we will focus on ethers, as they are the most common compounds that exhibit metamerism. 1. **Compound I**: `CH₃ - CH₂ - CH₂ - CH₂ - OH` (Alcohol) ...
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CH_(3)CH_(3)-underset(CHO)underset(|)overset(CH_(3))overset(|)C-CH_(2)CH_(3)

CH_(3)CH_(3)-underset(CHO)underset(|)overset(CH_(3))overset(|)C-CH_(2)CH_(3)

CH_(3)-underset(CH_(2))underset(||)(C )-CH_(2)OH ii CH_(3)-CH=CH-CHO

Among these chain isomers are : (I) CH_(3)-CH_(3)-CH_(2)-CH_(2)-OH (II) CH_(3)-CH_(2)-underset(OH)underset(|)(CH)-CH_(3) (III) CH_(3)-underset(CH_(3))underset(|)overset(OH)overset(|)(C)-CH_(3)

The IUPAC name of the compound CH_(3)underset(OH)underset(|)(CH)CH_(2)-underset(OH)underset(|)overset(CH_(3))overset(|4)(C)-CH_(3) is

The IUPAC name of the compound CH_(3)underset(OH)underset(|)(CH)CH_(2)-underset(OH)underset(|)overset(CH_(3))overset(|4)(C)-CH_(3) is

Write its IUPAC name CH_(3)-underset(CH_(3))underset(|)(CH)-CH_(2)-underset(CH_(2))underset(|)overset(CH_(3))overset(|)(C)-CH_(3)