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Draw the resonatin structure of (i) Oz...

Draw the resonatin structure of
(i) Ozone molecule (ii) Nitrate ion

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To draw the resonating structures of ozone (O₃) and the nitrate ion (NO₃⁻), we will follow these steps: ### Step 1: Draw the Lewis Structure of Ozone (O₃) 1. **Count the total valence electrons**: Oxygen has 6 valence electrons, and there are 3 oxygen atoms, so the total is 6 x 3 = 18 valence electrons. 2. **Arrange the atoms**: The central atom is usually the least electronegative, which in this case is one of the oxygen atoms. So, we have O-O-O. 3. **Distribute the electrons**: Start by forming single bonds between the central oxygen and the other two oxygens. This uses 4 electrons (2 bonds). 4. **Place remaining electrons**: Distribute the remaining 14 electrons to satisfy the octet rule. You will end up with one oxygen having a double bond with the central oxygen and one oxygen with a single bond. ### Step 2: Identify Resonating Structures of Ozone 1. **First Resonating Structure**: - One oxygen has a double bond with the central oxygen, while the other has a single bond. - Assign formal charges: The oxygen with a double bond has no charge, the central oxygen has a positive charge (+1), and the oxygen with a single bond has a negative charge (-1). 2. **Second Resonating Structure**: - Shift the double bond to the other oxygen. - Now, the first oxygen has a single bond and a negative charge, the central oxygen has a positive charge, and the second oxygen has a double bond with the central oxygen. ### Step 3: Draw the Resonance Hybrid for Ozone - The resonance hybrid shows that the bonds are not purely single or double but rather have partial double bond character. - Each oxygen will have a partial charge, with the central oxygen having a +1 charge and the terminal oxygens having a -1/2 charge. ### Step 4: Draw the Lewis Structure of Nitrate Ion (NO₃⁻) 1. **Count the total valence electrons**: Nitrogen has 5 valence electrons and each oxygen has 6. For NO₃⁻, we have 5 + (6 x 3) + 1 (for the negative charge) = 24 valence electrons. 2. **Arrange the atoms**: Place nitrogen in the center with three oxygens around it. 3. **Distribute the electrons**: Form single bonds between nitrogen and each oxygen. This uses 6 electrons. Distribute the remaining 18 electrons to satisfy the octet rule. ### Step 5: Identify Resonating Structures of Nitrate Ion 1. **First Resonating Structure**: - One oxygen has a double bond with nitrogen, while the other two have single bonds. - Assign formal charges: The nitrogen has a +1 charge, and one oxygen with a double bond has no charge, while the other two oxygens have a -1 charge each. 2. **Second Resonating Structure**: - Shift the double bond to one of the other oxygens. - The nitrogen still has a +1 charge, and the other two oxygens will have a -1 charge each. 3. **Third Resonating Structure**: - Shift the double bond to the third oxygen. - The nitrogen remains with a +1 charge, and the two oxygens with single bonds have a -1 charge each. ### Step 6: Draw the Resonance Hybrid for Nitrate Ion - The resonance hybrid shows that all N-O bonds are equivalent and have partial double bond character. - Each oxygen will have a charge of -2/3, and nitrogen will have a +1 charge. ### Summary - The resonating structures of ozone (O₃) involve two forms where the double bond shifts between the terminal oxygens. - The nitrate ion (NO₃⁻) has three resonating structures where the double bond shifts among the three oxygen atoms.

To draw the resonating structures of ozone (O₃) and the nitrate ion (NO₃⁻), we will follow these steps: ### Step 1: Draw the Lewis Structure of Ozone (O₃) 1. **Count the total valence electrons**: Oxygen has 6 valence electrons, and there are 3 oxygen atoms, so the total is 6 x 3 = 18 valence electrons. 2. **Arrange the atoms**: The central atom is usually the least electronegative, which in this case is one of the oxygen atoms. So, we have O-O-O. 3. **Distribute the electrons**: Start by forming single bonds between the central oxygen and the other two oxygens. This uses 4 electrons (2 bonds). 4. **Place remaining electrons**: Distribute the remaining 14 electrons to satisfy the octet rule. You will end up with one oxygen having a double bond with the central oxygen and one oxygen with a single bond. ...
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