Describe hybridisation in the case of `PCl_(5) and SF_(6)` The axial bonds are longer as compared to equatorial bonds in `PCl_(5)` whereas in `SF_(6)` both axial bonds and equatorial bonds and have the same bond length. Explain.

Explanation

To describe the hybridization in the case of \( PCl_5 \) and \( SF_6 \), and to explain the differences in bond lengths between axial and equatorial bonds in these molecules, we can follow these steps:

### Step 1: Determine the hybridization of \( PCl_5 \)

1. **Identify the central atom**: In \( PCl_5 \), phosphorus (P) is the central atom.
2. **Count the valence electrons**: Phosphorus has 5 valence electrons. Each chlorine (Cl) contributes 1 valence electron, and there are 5 chlorine atoms, contributing a total of 5 electrons.
3. **Calculate the total number of electrons**:
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