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The weight of an object at the centre of...

The weight of an object at the centre of the earth of radius R is

A

zero

B

infinite

C

R times the weight at the surface of the earth

D

`1//R^(2)` times the weight at the surface of the earth

Text Solution

Verified by Experts

The correct Answer is:
A
The weight of an object, w = mg
At the centre of the earth, acceleration due to gravity g zero. And is given by `g^(')=g(1-(h)/(R))` where h = distance from surface of the earth to centre of the earth and at
`centre(h=R)i.e.," "g^(')=0`.
`So," "w=mxx0=0`
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