An alkane `C_(8)H_(18)` is obtained as the only product on subjectiog a primary alkyl halide to wurtz reaction. On monobromination this alkane yieles a single isomer of a tertiary bromide . Write the structure of alkane and the tertiary bromide.

Explanation

To solve the problem, we need to identify the alkane \( C_8H_{18} \) that is produced from a primary alkyl halide through the Wurtz reaction and determine the structure of the tertiary bromide formed upon monobromination of this alkane.

### Step-by-Step Solution:

1. **Understanding the Wurtz Reaction**:
- The Wurtz reaction involves the coupling of two alkyl halides in the presence of sodium metal, resulting in the formation of a higher alkane. The general reaction doubles the number of carbon atoms.
- Since we are given \( C_8H_{18} \), we can infer that the initial alkyl halide must have had 4 carbon atoms, as two molecules of a 4-carbon alkyl halide would combine to form an 8-carbon alkane.

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