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Arrange the elements N, P, O and S in th...

Arrange the elements N, P, O and S in the order of
i) increasing first ionisation enthalpy.
ii) increasing non-metallic character.
Give reason for the arrangement assigned.

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The correct Answer is:
To solve the question of arranging the elements N (Nitrogen), P (Phosphorus), O (Oxygen), and S (Sulfur) in the order of increasing first ionization enthalpy and increasing non-metallic character, we will follow these steps: ### Step 1: Understanding Ionization Enthalpy **Definition**: Ionization enthalpy is the amount of energy required to remove an electron from an atom in its gaseous state. ### Step 2: Analyze the Elements - **Nitrogen (N)**: Atomic number 7, electronic configuration: 1s² 2s² 2p³ - **Oxygen (O)**: Atomic number 8, electronic configuration: 1s² 2s² 2p⁴ - **Phosphorus (P)**: Atomic number 15, electronic configuration: 1s² 2s² 2p⁶ 3s² 3p³ - **Sulfur (S)**: Atomic number 16, electronic configuration: 1s² 2s² 2p⁶ 3s² 3p⁴ ### Step 3: Arrange by Increasing First Ionization Enthalpy - **Trend**: Ionization enthalpy generally increases across a period (left to right) and decreases down a group (top to bottom). - **Comparing N and O**: Nitrogen has a half-filled p subshell (2p³), which is more stable than Oxygen's (2p⁴). Thus, Nitrogen has a higher ionization enthalpy than Oxygen. - **Comparing P and S**: Similarly, Phosphorus (3p³) has a half-filled subshell, making it more stable than Sulfur (3p⁴). Therefore, Phosphorus has a higher ionization enthalpy than Sulfur. - **Final Order**: The order of increasing first ionization enthalpy is: - Sulfur (S) < Phosphorus (P) < Oxygen (O) < Nitrogen (N) ### Step 4: Arrange by Increasing Non-Metallic Character **Definition**: Non-metallic character refers to the tendency of an element to gain electrons and form negative ions. - **Trend**: Non-metallic character increases across a period (left to right) and decreases down a group (top to bottom). - **Comparing N and O**: Oxygen is more non-metallic than Nitrogen because it is further right in the same period. - **Comparing P and S**: Sulfur is more non-metallic than Phosphorus for the same reason. - **Final Order**: The order of increasing non-metallic character is: - Phosphorus (P) < Sulfur (S) < Nitrogen (N) < Oxygen (O) ### Final Answers 1. **Increasing First Ionization Enthalpy**: S < P < O < N 2. **Increasing Non-Metallic Character**: P < S < N < O

To solve the question of arranging the elements N (Nitrogen), P (Phosphorus), O (Oxygen), and S (Sulfur) in the order of increasing first ionization enthalpy and increasing non-metallic character, we will follow these steps: ### Step 1: Understanding Ionization Enthalpy **Definition**: Ionization enthalpy is the amount of energy required to remove an electron from an atom in its gaseous state. ### Step 2: Analyze the Elements - **Nitrogen (N)**: Atomic number 7, electronic configuration: 1s² 2s² 2p³ - **Oxygen (O)**: Atomic number 8, electronic configuration: 1s² 2s² 2p⁴ ...
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  • Arrange in increasing order of s character

    A
    `sp^(3) lt sp^(2) lt sp`
    B
    `sp lt sp^(2) lt sp^(3)`
    C
    `sp^(2) lt sp lt sp^(3)`
    D
    `sp^(2) lt sp^(3) lt sp`
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