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Calculate the equilibrium constant for the reaction Fe(s)+Cd2+(aq)⇔Fe2+(aq)+Cd(s) (Given : E∘Cd2+∣Cd=0.40V,E∘Fe2+∣Fe=−0.44V).

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To calculate the equilibrium constant (Kc) for the reaction: \[ \text{Fe(s)} + \text{Cd}^{2+}(aq) \rightleftharpoons \text{Fe}^{2+}(aq) + \text{Cd(s)} \] we will follow these steps: ### Step 1: Identify the half-reactions From the given reaction, we can identify the oxidation and reduction half-reactions: ...
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