`KMnO_(4)` acts as on oxidising agent in alkaline medium. When alkaline `KMnO_(4)` is treated with `KI`, iodide ion is oxidised to `…………….`

Options

A. `I_(2)`
B. `IO^(-)`
C. `IO_(3)^(-)`
D. `IO_(4)^(-)`

Explanation

To solve the question regarding the oxidation of iodide ions by potassium permanganate (KMnO4) in alkaline medium, we can follow these steps:

### Step 1: Understand the Reactants
- **KMnO4** is a strong oxidizing agent, especially in alkaline conditions.
- **KI** (potassium iodide) contains iodide ions (I⁻), which can be oxidized.

### Step 2: Identify the Oxidation Process
- In alkaline medium, iodide ions (I⁻) are oxidized. The common oxidation product of iodide in alkaline conditions is iodate (IO3⁻).

### Step 3: Write the Balanced Chemical Equation
- The balanced equation for the reaction between KMnO4 and KI in alkaline medium can be represented as follows:

\[ 2 \text{KMnO}_4 + 6 \text{KI} + 6 \text{OH}^- \rightarrow 2 \text{MnO}_2 + 3 \text{I}_2 + 6 \text{KOH} + 3 \text{H}_2O \]

- However, since we are specifically interested in the oxidation of iodide ions to iodate, we can write the half-reaction for the iodide oxidation:

\[ 6 \text{I}^- + 6 \text{OH}^- \rightarrow 3 \text{IO}_3^- + 3 \text{H}_2O + 6 \text{e}^- \]

### Step 4: Conclusion
- From the above reactions, we can conclude that when iodide ions (I⁻) are oxidized by alkaline KMnO4, they are converted to iodate ions (IO3⁻).

### Final Answer
- The iodide ion (I⁻) is oxidized to **iodate ion (IO3⁻)**.

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