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A hydrocarbon 'A' (C(4)H(8)) on reaction...

A hydrocarbon 'A' `(C_(4)H_(8))` on reaction HCl gives a compound 'B', `(C_(4)H_(9)Cl)` which on reaction with 1 mol of `NH_(3)` gives compounds 'C' `(C_(4)H_(11)N)`. On reacting with `NaNO_(2)` and HCl followed by treatment with water compound 'C' yields an optically active alcohol, 'D'. Ozonolysis of 'A' given 2mols of acetyldehyde. Identify compound 'A' to 'D'. Explain the reaction involved.

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To solve the problem step by step, we will identify compounds A, B, C, and D based on the given reactions and information. ### Step 1: Identify Compound A The question states that hydrocarbon A (C₄H₈) undergoes ozonolysis to yield two moles of acetaldehyde (CH₃CHO). The ozonolysis of an alkene typically breaks the double bond and forms carbonyl compounds. Given that ozonolysis produces two moles of acetaldehyde, we can deduce that compound A must be 2-butene (CH₃-CH=CH-CH₃). This is because the ozonolysis of 2-butene results in two moles of acetaldehyde. **Compound A:** 2-butene (CH₃-CH=CH-CH₃) ...
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A hydrocarbon 'A', (C_4H_8) on reaction with HCl gives a compound 'B', (C_4H_9Cl) , which on reaction with 1 mol of NH_3 gives compound 'C', (C_4H_11N) . On reacting with NaNO_2 and HCl followed by treatment with water, compound 'C' yields an optically active alcohol, 'D'. Ozonolysis of 'A' gives 2 moles of acetaldehyde. Identify compounds 'A' to 'D'. Explain the reactions involved.

A hydrocarbon 'A', (C_4H_8) on reaction with HCl gives a compound 'B', (C_4H_9Cl) , which on reaction with 1 mol of NH_3 gives compound 'C', (C_4H_11N) . On reacting with NaNO_2 and HCl followed by treatment with water, compound 'C' yields an optically active alcohol, 'D'. Ozonolysis of 'A' gives 2 moles of acetaldehyde. Identify compounds 'A' to 'D'. Explain the reactions involved.

Knowledge Check

  • Compound A (C_(7)H_(14)) decolourises Br_(2) in C Cl_(4) and reacts with Hg(OAc)_(2) followed by reduction with NaBH_(4) to produce a resolvable compound B. A undergoes reductive ozonolysis to give as one of the compound. Identify A and B.

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  • Optically active isomer (A) of (C_5H_9 Cl) on treatment with one mole of H2 gives an optically inactive compound (B) compound (A) will be :

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