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The figure obtained by joining the mid-p...

The figure obtained by joining the mid-points of the adjacent sides of a rectangle of sides 8 cm and 6 cm, is

A

a rectangle of area `24 cm^(2)`

B

a square of area `25 cm^(2)`

C

a trapezium of area `24 cm^(2)`

D

a rhombus of area `24 cm^(2)`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the figure obtained by joining the midpoints of the adjacent sides of a rectangle with sides 8 cm and 6 cm, and then calculate the area of that figure. ### Step-by-Step Solution: 1. **Identify the Rectangle**: - We have a rectangle ABCD where AB = 8 cm (length) and BC = 6 cm (breadth). - Let's label the vertices: A(0, 0), B(8, 0), C(8, 6), D(0, 6). **Hint**: Start by sketching the rectangle and labeling the vertices. 2. **Find the Midpoints**: - The midpoints of the sides are: - E (midpoint of AB) = ((0 + 8)/2, (0 + 0)/2) = (4, 0) - F (midpoint of BC) = ((8 + 8)/2, (0 + 6)/2) = (8, 3) - G (midpoint of CD) = ((8 + 0)/2, (6 + 6)/2) = (4, 6) - H (midpoint of DA) = ((0 + 0)/2, (6 + 0)/2) = (0, 3) **Hint**: Use the midpoint formula: Midpoint = ((x1 + x2)/2, (y1 + y2)/2). 3. **Connect the Midpoints**: - Now, connect the points E, F, G, and H in order to form a quadrilateral. **Hint**: Draw lines connecting the points E, F, G, and H sequentially. 4. **Identify the Figure**: - The quadrilateral EFGH formed by joining the midpoints is a rhombus. This is because the diagonals of the rhombus bisect each other at right angles and the opposite sides are equal. **Hint**: Recall that in a rectangle, joining the midpoints of adjacent sides always forms a rhombus. 5. **Calculate the Diagonals**: - The diagonals of the rhombus are: - Diagonal 1 (EF) = Distance between E(4, 0) and G(4, 6) = 6 cm - Diagonal 2 (FH) = Distance between F(8, 3) and H(0, 3) = 8 cm **Hint**: Use the distance formula to find the lengths of the diagonals. 6. **Calculate the Area of the Rhombus**: - The area of a rhombus can be calculated using the formula: \[ \text{Area} = \frac{1}{2} \times \text{Diagonal 1} \times \text{Diagonal 2} \] - Substituting the values: \[ \text{Area} = \frac{1}{2} \times 6 \times 8 = \frac{48}{2} = 24 \text{ cm}^2 \] **Hint**: Remember to multiply the diagonals and divide by 2 to find the area. ### Final Answer: The figure obtained by joining the midpoints of the adjacent sides of the rectangle is a rhombus with an area of 24 cm².

To solve the problem, we need to find the figure obtained by joining the midpoints of the adjacent sides of a rectangle with sides 8 cm and 6 cm, and then calculate the area of that figure. ### Step-by-Step Solution: 1. **Identify the Rectangle**: - We have a rectangle ABCD where AB = 8 cm (length) and BC = 6 cm (breadth). - Let's label the vertices: A(0, 0), B(8, 0), C(8, 6), D(0, 6). ...
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