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A point E is taken on the side BC of a p...

A point E is taken on the side BC of a parallelogram ABCD. AE and DC are produced to meet at F. Prove that `ar(DeltaADF) = ar (ABFC)`.

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To prove that the area of triangle ADF is equal to the area of quadrilateral ABFC, we will follow these steps: ### Step-by-Step Solution 1. **Identify the Parallelogram and the Triangles**: We have a parallelogram ABCD with point E on side BC. Lines AE and DC are extended to meet at point F. 2. **Use the Property of Diagonals**: ...
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