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Which of the following equations has two...

Which of the following equations has two distinct real roots?

A

`2x^(2)-3sqrt(2)x+9/4=0`

B

`x^(2)+x-5=0`

C

`x^(2)+3x+2sqrt(2)=0`

D

`5x^(2)-3x+1=0`

Text Solution

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The correct Answer is:
To determine which of the given quadratic equations has two distinct real roots, we need to use the concept of the discriminant. The discriminant \( D \) of a quadratic equation in the form \( ax^2 + bx + c = 0 \) is given by the formula: \[ D = b^2 - 4ac \] A quadratic equation has: - Two distinct real roots if \( D > 0 \) - One real root (or two equal roots) if \( D = 0 \) - No real roots if \( D < 0 \) Now, let's analyze each option step by step. ### Step 1: Analyze the first equation Assume the first equation is \( 2x^2 - 3\sqrt{2}x + \frac{9}{4} = 0 \). - Here, \( a = 2 \), \( b = -3\sqrt{2} \), and \( c = \frac{9}{4} \). - Calculate the discriminant: \[ D = (-3\sqrt{2})^2 - 4 \cdot 2 \cdot \frac{9}{4} \] \[ D = 18 - 18 = 0 \] Since \( D = 0 \), this equation does not have two distinct real roots. ### Step 2: Analyze the second equation Assume the second equation is \( x^2 + x - 5 = 0 \). - Here, \( a = 1 \), \( b = 1 \), and \( c = -5 \). - Calculate the discriminant: \[ D = (1)^2 - 4 \cdot 1 \cdot (-5) \] \[ D = 1 + 20 = 21 \] Since \( D > 0 \), this equation has two distinct real roots. ### Step 3: Analyze the third equation Assume the third equation is \( x^2 + 3x + 2\sqrt{2} = 0 \). - Here, \( a = 1 \), \( b = 3 \), and \( c = 2\sqrt{2} \). - Calculate the discriminant: \[ D = (3)^2 - 4 \cdot 1 \cdot (2\sqrt{2}) \] \[ D = 9 - 8\sqrt{2} \] Since \( \sqrt{2} \approx 1.414 \), we have \( 8\sqrt{2} \approx 11.312 \), thus: \[ D \approx 9 - 11.312 < 0 \] Since \( D < 0 \), this equation does not have two distinct real roots. ### Step 4: Analyze the fourth equation Assume the fourth equation is \( 5x^2 - 3x + 1 = 0 \). - Here, \( a = 5 \), \( b = -3 \), and \( c = 1 \). - Calculate the discriminant: \[ D = (-3)^2 - 4 \cdot 5 \cdot 1 \] \[ D = 9 - 20 = -11 \] Since \( D < 0 \), this equation does not have two distinct real roots. ### Conclusion Among the given options, only the second equation \( x^2 + x - 5 = 0 \) has two distinct real roots.

To determine which of the given quadratic equations has two distinct real roots, we need to use the concept of the discriminant. The discriminant \( D \) of a quadratic equation in the form \( ax^2 + bx + c = 0 \) is given by the formula: \[ D = b^2 - 4ac \] A quadratic equation has: - Two distinct real roots if \( D > 0 \) ...
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