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If sin(theta+alpha)=aa n dsin(theta+beta...

If `sin(theta+alpha)=aa n dsin(theta+beta)=b ,` prove that `cos2(alpha-beta)-4a bcos(alpha-beta)=1-2a^2-2b^2`

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To prove the equation \( \cos(2(\alpha - \beta)) - 4ab \cos(\alpha - \beta) = 1 - 2a^2 - 2b^2 \), we start with the given expressions: 1. **Given:** \[ \sin(\theta + \alpha) = a \] \[ \sin(\theta + \beta) = b ...
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