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Let the relation R be defined in N by aR...

Let the relation `R` be defined in `N` by `aRb`, if `2a + 3b = 30`. Then `R` = …… .

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To solve the problem, we need to find the set of ordered pairs \((a, b)\) in the relation \(R\) defined by the equation \(2a + 3b = 30\), where \(a\) and \(b\) are natural numbers (i.e., \(N\)). ### Step-by-Step Solution: 1. **Start with the given equation**: \[ 2a + 3b = 30 \] ...
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Knowledge Check

  • Let L denote the set of all straight lines in a plane. Let a relation R be defined by a R b hArr a bot b, AA a, b in L . Then, R is

    A
    Reflexive only
    B
    Symmetric only
    C
    Transitive only
    D
    None of these

  • Let R be the relation in set N, given by R= {(a,b): a = b-2,b gt 6} . Then,

    A
    `(8,7) inR`
    B
    `(6,8) inR`
    C
    `(3,8) inR`
    D
    `(2,4) inR`

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