Home
Class 12
MATHS
Every function is invertible....

Every function is invertible.

Text Solution

AI Generated Solution

The correct Answer is:
To determine whether the statement "Every function is invertible" is true or false, we can follow these steps: ### Step 1: Understand the Definition of Invertible Functions A function is said to be invertible if there exists another function that can reverse its mapping. For a function to be invertible, it must be a bijection, meaning it is both one-to-one (injective) and onto (surjective). ### Step 2: Identify the Conditions for Invertibility - **One-to-One (Injective)**: Each element in the domain maps to a unique element in the codomain. No two different inputs produce the same output. - **Onto (Surjective)**: Every element in the codomain is an image of at least one element from the domain. ### Step 3: Analyze the Statement The statement claims that every function is invertible. However, not all functions meet the criteria of being bijective. ### Step 4: Provide a Counterexample Consider the function \( f: \{1, 2, 3, 4\} \to \{2, 1, 2, 5\} \) defined as: - \( f(1) = 2 \) - \( f(2) = 1 \) - \( f(3) = 2 \) - \( f(4) = 5 \) In this case: - The output \( 2 \) is produced by both inputs \( 1 \) and \( 3 \). Thus, the function is not one-to-one (not injective). - Since the function is not injective, it cannot have an inverse that is also a function. ### Step 5: Conclusion Since we have shown that not all functions are invertible (using the counterexample), we can conclude that the statement "Every function is invertible" is **false**. Only bijective functions are invertible. ### Final Answer The statement "Every function is invertible" is **false**. ---

To determine whether the statement "Every function is invertible" is true or false, we can follow these steps: ### Step 1: Understand the Definition of Invertible Functions A function is said to be invertible if there exists another function that can reverse its mapping. For a function to be invertible, it must be a bijection, meaning it is both one-to-one (injective) and onto (surjective). ### Step 2: Identify the Conditions for Invertibility - **One-to-One (Injective)**: Each element in the domain maps to a unique element in the codomain. No two different inputs produce the same output. - **Onto (Surjective)**: Every element in the codomain is an image of at least one element from the domain. ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • RELATIONS AND FUNCTIONS

    NCERT EXEMPLAR ENGLISH|Exercise Objective Type Questions|20 Videos
  • PROBABILITY

    NCERT EXEMPLAR ENGLISH|Exercise True/False|9 Videos
  • THREE DIMENSIONAL GEOMETRY

    NCERT EXEMPLAR ENGLISH|Exercise LONG ANSWER TYPE QUESTIONS|16 Videos

Similar Questions

Explore conceptually related problems

Determine f^(-1)(x) , if given function is invertible. f:(-oo,1)to(-oo,-2) defined by f(x)=-(x+1)^(2)-2

Show that the binary operation * on A=R-{-1} defined as a*b=a+b+a b for all a ,bA is commutative and associative on Adot Also find the identity element of * in A and prove that every element of A is invertible.

Show that the binary operation * on A=R-{-1} defined as a*b=a+b+a b for all a ,bA is commutative and associative on Adot Also find the identity element of * in A and prove that every element of A is invertible.

Using the definition, Prove that the function f:A to B is invertible if and only if f is both one-one and onto.

Let * be a binary operation on set Q-[1] defined by a*b=a+b-a b for all a , b in Q-[1]dot Find the identity element with respect to *onQdot Also, prove that every element of Q-[1] is invertible.

Let * be a binary operation on set Q-[1] defined by a*b=a+b-a b for all a , b in Q-[1]dot Find the identity element with respect to *onQdot Also, prove that every element of Q-[1] is invertible.

On Q, the set of all rational numbers, a binary operation * is defined by a*b=(a b)/5 for all a , b in Qdot Find the identity element for * in Q. Also, prove that every non-zero element of Q is invertible.

On Q, the set of all rational numbers, a binary operation * is defined by a*b=(a b)/5 for all a , b in Qdot Find the identity element for * in Q. Also, prove that every non-zero element of Q is invertible.

Let * be a binary operation on Q-{-1} defined by a*b=a+b+a b for all a ,\ b in Q-{-1} . Then, Show that every element of Q-{-1} is invertible. Also, find the inverse of an arbitrary element.

On R-[1] , a binary operation * is defined by a*b=a+b-a b . Prove that * is commutative and associative. Find the identity element for * on R-[1]dot Also, prove that every element of R-[1] is invertible.